11=3t-2(t+12)

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Solution for 11=3t-2(t+12) equation: 



11=3t-2(t+12)

We move all terms to the left:

11-(3t-2(t+12))=0



We calculate terms in parentheses: -(3t-2(t+12)), so:

3t-2(t+12)

We multiply parentheses

3t-2t-24

We add all the numbers together, and all the variables

t-24

Back to the equation:

-(t-24)



We get rid of parentheses

-t+24+11=0

We add all the numbers together, and all the variables

-1t+35=0

We move all terms containing t to the left, all other terms to the right

-t=-35

t=-35/-1

t=+35

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