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11=4(x2)-(x-7)
We move all terms to the left:
11-(4(x2)-(x-7))=0
We calculate terms in parentheses: -(4x2-(x-7)), so:We get rid of parentheses
4x2-(x-7)
We add all the numbers together, and all the variables
4x^2-(x-7)
We get rid of parentheses
4x^2-x+7
We add all the numbers together, and all the variables
4x^2-1x+7
Back to the equation:
-(4x^2-1x+7)
-4x^2+1x-7+11=0
We add all the numbers together, and all the variables
-4x^2+x+4=0
a = -4; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·(-4)·4
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{65}}{2*-4}=\frac{-1-\sqrt{65}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{65}}{2*-4}=\frac{-1+\sqrt{65}}{-8} $
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