11=5(3b-4)+1

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Solution for 11=5(3b-4)+1 equation:



11=5(3b-4)+1
We move all terms to the left:
11-(5(3b-4)+1)=0
We calculate terms in parentheses: -(5(3b-4)+1), so:
5(3b-4)+1
We multiply parentheses
15b-20+1
We add all the numbers together, and all the variables
15b-19
Back to the equation:
-(15b-19)
We get rid of parentheses
-15b+19+11=0
We add all the numbers together, and all the variables
-15b+30=0
We move all terms containing b to the left, all other terms to the right
-15b=-30
b=-30/-15
b=+2

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