11=5(x+2)-4(3-2x)

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Solution for 11=5(x+2)-4(3-2x) equation: 



11=5(x+2)-4(3-2x)

We move all terms to the left:

11-(5(x+2)-4(3-2x))=0

We add all the numbers together, and all the variables

-(5(x+2)-4(-2x+3))+11=0



We calculate terms in parentheses: -(5(x+2)-4(-2x+3)), so:

5(x+2)-4(-2x+3)

We multiply parentheses

5x+8x+10-12

We add all the numbers together, and all the variables

13x-2

Back to the equation:

-(13x-2)



We get rid of parentheses

-13x+2+11=0

We add all the numbers together, and all the variables

-13x+13=0

We move all terms containing x to the left, all other terms to the right

-13x=-13

x=-13/-13

x=1

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