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11=9+3/z
We move all terms to the left:
11-(9+3/z)=0
Domain of the equation: z)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
-(3/z+9)+11=0
We get rid of parentheses
-3/z-9+11=0
We multiply all the terms by the denominator
-9*z+11*z-3=0
We add all the numbers together, and all the variables
2z-3=0
We move all terms containing z to the left, all other terms to the right
2z=3
z=3/2
z=1+1/2
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