11X*40x=4922

Solution for 11X*40x=4922 equation:

11X*40X=4922

We move all terms to the left:

11X*40X-(4922)=0

Wy multiply elements

440X^2-4922=0

a = 440; b = 0; c = -4922;
Δ = b2-4ac
Δ = 02-4·440·(-4922)
Δ = 8662720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8662720}=\sqrt{64*135355}=\sqrt{64}*\sqrt{135355}=8\sqrt{135355}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{135355}}{2*440}=\frac{0-8\sqrt{135355}}{880}
=-\frac{8\sqrt{135355}}{880}
=-\frac{\sqrt{135355}}{110}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{135355}}{2*440}=\frac{0+8\sqrt{135355}}{880}
=\frac{8\sqrt{135355}}{880}
=\frac{\sqrt{135355}}{110}
$