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11X*40X=4922
We move all terms to the left:
11X*40X-(4922)=0
Wy multiply elements
440X^2-4922=0
a = 440; b = 0; c = -4922;
Δ = b2-4ac
Δ = 02-4·440·(-4922)
Δ = 8662720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8662720}=\sqrt{64*135355}=\sqrt{64}*\sqrt{135355}=8\sqrt{135355}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{135355}}{2*440}=\frac{0-8\sqrt{135355}}{880} =-\frac{8\sqrt{135355}}{880} =-\frac{\sqrt{135355}}{110} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{135355}}{2*440}=\frac{0+8\sqrt{135355}}{880} =\frac{8\sqrt{135355}}{880} =\frac{\sqrt{135355}}{110} $
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