11a+20=3a(2)

Solution for 11a+20=3a(2) equation:

11a+20=3a(2)

We move all terms to the left:

11a+20-(3a(2))=0

determiningTheFunctionDomain
11a-3a2+20=0

We add all the numbers together, and all the variables

-3a^2+11a+20=0

a = -3; b = 11; c = +20;
Δ = b2-4ac
Δ = 112-4·(-3)·20
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*-3}=\frac{-30}{-6}
=+5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*-3}=\frac{8}{-6}
=-1+1/3
$