11a+4a+(-3a)+(-13a)=2

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Solution for 11a+4a+(-3a)+(-13a)=2 equation: 



11a+4a+(-3a)+(-13a)=2

We move all terms to the left:

11a+4a+(-3a)+(-13a)-(2)=0

We add all the numbers together, and all the variables

15a+(-3a)+(-13a)-2=0

We get rid of parentheses

15a-3a-13a-2=0

We add all the numbers together, and all the variables

-1a-2=0

We move all terms containing a to the left, all other terms to the right

-a=2

a=2/-1

a=-2

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