11a+4a+2-5=3(5a)

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Solution for 11a+4a+2-5=3(5a) equation: 



11a+4a+2-5=3(5a)

We move all terms to the left:

11a+4a+2-5-(3(5a))=0

determiningTheFunctionDomain
11a+4a-35a+2-5=0

We add all the numbers together, and all the variables

-20a-3=0

We move all terms containing a to the left, all other terms to the right

-20a=3

a=3/-20

a=-3/20

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