11a+8=-2(1-4a)+a

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Solution for 11a+8=-2(1-4a)+a equation: 



11a+8=-2(1-4a)+a

We move all terms to the left:

11a+8-(-2(1-4a)+a)=0

We add all the numbers together, and all the variables

11a-(-2(-4a+1)+a)+8=0



We calculate terms in parentheses: -(-2(-4a+1)+a), so:

-2(-4a+1)+a

We add all the numbers together, and all the variables

a-2(-4a+1)

We multiply parentheses

a+8a-2

We add all the numbers together, and all the variables

9a-2

Back to the equation:

-(9a-2)



We get rid of parentheses

11a-9a+2+8=0

We add all the numbers together, and all the variables

2a+10=0

We move all terms containing a to the left, all other terms to the right

2a=-10

a=-10/2

a=-5

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