11a-3(a+1)=2(a-2)

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Solution for 11a-3(a+1)=2(a-2) equation: 



11a-3(a+1)=2(a-2)

We move all terms to the left:

11a-3(a+1)-(2(a-2))=0

We multiply parentheses

11a-3a-(2(a-2))-3=0



We calculate terms in parentheses: -(2(a-2)), so:

2(a-2)

We multiply parentheses

2a-4

Back to the equation:

-(2a-4)



We add all the numbers together, and all the variables

8a-(2a-4)-3=0

We get rid of parentheses

8a-2a+4-3=0

We add all the numbers together, and all the variables

6a+1=0

We move all terms containing a to the left, all other terms to the right

6a=-1

a=-1/6

a=-1/6

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