11a-3(a+4)=4(3a-1)

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Solution for 11a-3(a+4)=4(3a-1) equation: 



11a-3(a+4)=4(3a-1)

We move all terms to the left:

11a-3(a+4)-(4(3a-1))=0

We multiply parentheses

11a-3a-(4(3a-1))-12=0



We calculate terms in parentheses: -(4(3a-1)), so:

4(3a-1)

We multiply parentheses

12a-4

Back to the equation:

-(12a-4)



We add all the numbers together, and all the variables

8a-(12a-4)-12=0

We get rid of parentheses

8a-12a+4-12=0

We add all the numbers together, and all the variables

-4a-8=0

We move all terms containing a to the left, all other terms to the right

-4a=8

a=8/-4

a=-2

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