11a-5(a+1)=3(a-2)

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Solution for 11a-5(a+1)=3(a-2) equation: 



11a-5(a+1)=3(a-2)

We move all terms to the left:

11a-5(a+1)-(3(a-2))=0

We multiply parentheses

11a-5a-(3(a-2))-5=0



We calculate terms in parentheses: -(3(a-2)), so:

3(a-2)

We multiply parentheses

3a-6

Back to the equation:

-(3a-6)



We add all the numbers together, and all the variables

6a-(3a-6)-5=0

We get rid of parentheses

6a-3a+6-5=0

We add all the numbers together, and all the variables

3a+1=0

We move all terms containing a to the left, all other terms to the right

3a=-1

a=-1/3

a=-1/3

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