11b2=13

Solution for 11b2=13 equation:

11b^2=13

We move all terms to the left:

11b^2-(13)=0

a = 11; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·11·(-13)
Δ = 572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{572}=\sqrt{4*143}=\sqrt{4}*\sqrt{143}=2\sqrt{143}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{143}}{2*11}=\frac{0-2\sqrt{143}}{22}
=-\frac{2\sqrt{143}}{22}
=-\frac{\sqrt{143}}{11}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{143}}{2*11}=\frac{0+2\sqrt{143}}{22}
=\frac{2\sqrt{143}}{22}
=\frac{\sqrt{143}}{11}
$