11c+10=3(2c+4)

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Solution for 11c+10=3(2c+4) equation: 



11c+10=3(2c+4)

We move all terms to the left:

11c+10-(3(2c+4))=0



We calculate terms in parentheses: -(3(2c+4)), so:

3(2c+4)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

11c-6c-12+10=0

We add all the numbers together, and all the variables

5c-2=0

We move all terms containing c to the left, all other terms to the right

5c=2

c=2/5

c=2/5

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