11c-2(2c+1)=3(c-6)

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Solution for 11c-2(2c+1)=3(c-6) equation:


Simplifying
11c + -2(2c + 1) = 3(c + -6)

Reorder the terms:
11c + -2(1 + 2c) = 3(c + -6)
11c + (1 * -2 + 2c * -2) = 3(c + -6)
11c + (-2 + -4c) = 3(c + -6)

Reorder the terms:
-2 + 11c + -4c = 3(c + -6)

Combine like terms: 11c + -4c = 7c
-2 + 7c = 3(c + -6)

Reorder the terms:
-2 + 7c = 3(-6 + c)
-2 + 7c = (-6 * 3 + c * 3)
-2 + 7c = (-18 + 3c)

Solving
-2 + 7c = -18 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-2 + 7c + -3c = -18 + 3c + -3c

Combine like terms: 7c + -3c = 4c
-2 + 4c = -18 + 3c + -3c

Combine like terms: 3c + -3c = 0
-2 + 4c = -18 + 0
-2 + 4c = -18

Add '2' to each side of the equation.
-2 + 2 + 4c = -18 + 2

Combine like terms: -2 + 2 = 0
0 + 4c = -18 + 2
4c = -18 + 2

Combine like terms: -18 + 2 = -16
4c = -16

Divide each side by '4'.
c = -4

Simplifying
c = -4

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