11d(2)=22d

Solution for 11d(2)=22d equation:

11d(2)=22d

We move all terms to the left:

11d(2)-(22d)=0

We add all the numbers together, and all the variables

11d^2-22d=0

a = 11; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·11·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*11}=\frac{0}{22}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*11}=\frac{44}{22}
=2
$