11h(h-2)=6h+3

Solution for 11h(h-2)=6h+3 equation:

11h(h-2)=6h+3

We move all terms to the left:

11h(h-2)-(6h+3)=0

We multiply parentheses

11h^2-22h-(6h+3)=0

We get rid of parentheses

11h^2-22h-6h-3=0

We add all the numbers together, and all the variables

11h^2-28h-3=0

a = 11; b = -28; c = -3;
Δ = b2-4ac
Δ = -282-4·11·(-3)
Δ = 916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{916}=\sqrt{4*229}=\sqrt{4}*\sqrt{229}=2\sqrt{229}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{229}}{2*11}=\frac{28-2\sqrt{229}}{22}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{229}}{2*11}=\frac{28+2\sqrt{229}}{22}
$