11h2-12h+1=0

Solution for 11h2-12h+1=0 equation:

11h^2-12h+1=0

a = 11; b = -12; c = +1;
Δ = b2-4ac
Δ = -122-4·11·1
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-10}{2*11}=\frac{2}{22}
=1/11
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+10}{2*11}=\frac{22}{22}
=1
$