11m+7(-m-11)=-3(m-5)+11m

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Solution for 11m+7(-m-11)=-3(m-5)+11m equation: 



11m+7(-m-11)=-3(m-5)+11m

We move all terms to the left:

11m+7(-m-11)-(-3(m-5)+11m)=0

We add all the numbers together, and all the variables

11m+7(-1m-11)-(-3(m-5)+11m)=0

We multiply parentheses

11m-7m-(-3(m-5)+11m)-77=0



We calculate terms in parentheses: -(-3(m-5)+11m), so:

-3(m-5)+11m

We add all the numbers together, and all the variables

11m-3(m-5)

We multiply parentheses

11m-3m+15

We add all the numbers together, and all the variables

8m+15

Back to the equation:

-(8m+15)



We add all the numbers together, and all the variables

4m-(8m+15)-77=0

We get rid of parentheses

4m-8m-15-77=0

We add all the numbers together, and all the variables

-4m-92=0

We move all terms containing m to the left, all other terms to the right

-4m=92

m=92/-4

m=-23

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