11m2+14=47

Solution for 11m2+14=47 equation:

11m^2+14=47

We move all terms to the left:

11m^2+14-(47)=0

We add all the numbers together, and all the variables

11m^2-33=0

a = 11; b = 0; c = -33;
Δ = b2-4ac
Δ = 02-4·11·(-33)
Δ = 1452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1452}=\sqrt{484*3}=\sqrt{484}*\sqrt{3}=22\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{3}}{2*11}=\frac{0-22\sqrt{3}}{22}
=-\frac{22\sqrt{3}}{22}
=-\sqrt{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{3}}{2*11}=\frac{0+22\sqrt{3}}{22}
=\frac{22\sqrt{3}}{22}
=\sqrt{3}
$