11m2+7m-4=0

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Solution for 11m2+7m-4=0 equation:



11m^2+7m-4=0
a = 11; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·11·(-4)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-15}{2*11}=\frac{-22}{22} =-1 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+15}{2*11}=\frac{8}{22} =4/11 $

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