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11m^2+7m-4=0
a = 11; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·11·(-4)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-15}{2*11}=\frac{-22}{22} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+15}{2*11}=\frac{8}{22} =4/11 $
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