11n2=-27n

Solution for 11n2=-27n equation:

11n^2=-27n

We move all terms to the left:

11n^2-(-27n)=0

We get rid of parentheses

11n^2+27n=0

a = 11; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·11·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*11}=\frac{-54}{22}
=-2+5/11
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*11}=\frac{0}{22}
=0
$