11p-11(9-4p)=2(p-2)+11

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Solution for 11p-11(9-4p)=2(p-2)+11 equation: 



11p-11(9-4p)=2(p-2)+11

We move all terms to the left:

11p-11(9-4p)-(2(p-2)+11)=0

We add all the numbers together, and all the variables

11p-11(-4p+9)-(2(p-2)+11)=0

We multiply parentheses

11p+44p-(2(p-2)+11)-99=0



We calculate terms in parentheses: -(2(p-2)+11), so:

2(p-2)+11

We multiply parentheses

2p-4+11

We add all the numbers together, and all the variables

2p+7

Back to the equation:

-(2p+7)



We add all the numbers together, and all the variables

55p-(2p+7)-99=0

We get rid of parentheses

55p-2p-7-99=0

We add all the numbers together, and all the variables

53p-106=0

We move all terms containing p to the left, all other terms to the right

53p=106

p=106/53

p=2

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