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11r+15=12r^2
We move all terms to the left:
11r+15-(12r^2)=0
determiningTheFunctionDomain -12r^2+11r+15=0
a = -12; b = 11; c = +15;
Δ = b2-4ac
Δ = 112-4·(-12)·15
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-29}{2*-12}=\frac{-40}{-24} =1+2/3 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+29}{2*-12}=\frac{18}{-24} =-3/4 $
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