11r-3(r+4)=5(4r-5)-11

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Solution for 11r-3(r+4)=5(4r-5)-11 equation: 



11r-3(r+4)=5(4r-5)-11

We move all terms to the left:

11r-3(r+4)-(5(4r-5)-11)=0

We multiply parentheses

11r-3r-(5(4r-5)-11)-12=0



We calculate terms in parentheses: -(5(4r-5)-11), so:

5(4r-5)-11

We multiply parentheses

20r-25-11

We add all the numbers together, and all the variables

20r-36

Back to the equation:

-(20r-36)



We add all the numbers together, and all the variables

8r-(20r-36)-12=0

We get rid of parentheses

8r-20r+36-12=0

We add all the numbers together, and all the variables

-12r+24=0

We move all terms containing r to the left, all other terms to the right

-12r=-24

r=-24/-12

r=+2

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