11s2=23s

Solution for 11s2=23s equation:

11s^2=23s

We move all terms to the left:

11s^2-(23s)=0

a = 11; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·11·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*11}=\frac{0}{22}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*11}=\frac{46}{22}
=2+1/11
$