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11w^2-621=9205-23w^2
We move all terms to the left:
11w^2-621-(9205-23w^2)=0
We get rid of parentheses
11w^2+23w^2-9205-621=0
We add all the numbers together, and all the variables
34w^2-9826=0
a = 34; b = 0; c = -9826;
Δ = b2-4ac
Δ = 02-4·34·(-9826)
Δ = 1336336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1336336}=1156$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1156}{2*34}=\frac{-1156}{68} =-17 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1156}{2*34}=\frac{1156}{68} =17 $
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