11x(4x+7)+16=4x

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Solution for 11x(4x+7)+16=4x equation:



11x(4x+7)+16=4x
We move all terms to the left:
11x(4x+7)+16-(4x)=0
We add all the numbers together, and all the variables
-4x+11x(4x+7)+16=0
We multiply parentheses
44x^2-4x+77x+16=0
We add all the numbers together, and all the variables
44x^2+73x+16=0
a = 44; b = 73; c = +16;
Δ = b2-4ac
Δ = 732-4·44·16
Δ = 2513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-\sqrt{2513}}{2*44}=\frac{-73-\sqrt{2513}}{88} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+\sqrt{2513}}{2*44}=\frac{-73+\sqrt{2513}}{88} $

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