11x(x+2)+10x-3=4(8x+134)

Solution for 11x(x+2)+10x-3=4(8x+134) equation:

11x(x+2)+10x-3=4(8x+134)

We move all terms to the left:

11x(x+2)+10x-3-(4(8x+134))=0

We add all the numbers together, and all the variables

10x+11x(x+2)-(4(8x+134))-3=0

We multiply parentheses

11x^2+10x+22x-(4(8x+134))-3=0


We calculate terms in parentheses: -(4(8x+134)), so:

4(8x+134)

We multiply parentheses

32x+536

Back to the equation:

-(32x+536)


We add all the numbers together, and all the variables

11x^2+32x-(32x+536)-3=0

We get rid of parentheses

11x^2+32x-32x-536-3=0

We add all the numbers together, and all the variables

11x^2-539=0

a = 11; b = 0; c = -539;
Δ = b2-4ac
Δ = 02-4·11·(-539)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-154}{2*11}=\frac{-154}{22}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+154}{2*11}=\frac{154}{22}
=7
$