11x*2+x*2=(4x+8)(3x-3)

Solution for 11x*2+x*2=(4x+8)(3x-3) equation:

11x*2+x*2=(4x+8)(3x-3)

We move all terms to the left:

11x*2+x*2-((4x+8)(3x-3))=0

Wy multiply elements

22x+2x-((4x+8)(3x-3))=0

We multiply parentheses ..

-((+12x^2-12x+24x-24))+22x+2x=0


We calculate terms in parentheses: -((+12x^2-12x+24x-24)), so:

(+12x^2-12x+24x-24)

We get rid of parentheses

12x^2-12x+24x-24

We add all the numbers together, and all the variables

12x^2+12x-24

Back to the equation:

-(12x^2+12x-24)


We add all the numbers together, and all the variables

24x-(12x^2+12x-24)=0

We get rid of parentheses

-12x^2+24x-12x+24=0

We add all the numbers together, and all the variables

-12x^2+12x+24=0

a = -12; b = 12; c = +24;
Δ = b2-4ac
Δ = 122-4·(-12)·24
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*-12}=\frac{-48}{-24}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*-12}=\frac{24}{-24}
=-1
$