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11x*x+41x=1586
We move all terms to the left:
11x*x+41x-(1586)=0
We add all the numbers together, and all the variables
41x+11x*x-1586=0
Wy multiply elements
11x^2+41x-1586=0
a = 11; b = 41; c = -1586;
Δ = b2-4ac
Δ = 412-4·11·(-1586)
Δ = 71465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{71465}}{2*11}=\frac{-41-\sqrt{71465}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{71465}}{2*11}=\frac{-41+\sqrt{71465}}{22} $
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