11x+(160-4x)=300

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Solution for 11x+(160-4x)=300 equation: 



11x+(160-4x)=300

We move all terms to the left:

11x+(160-4x)-(300)=0

We add all the numbers together, and all the variables

11x+(-4x+160)-300=0

We get rid of parentheses

11x-4x+160-300=0

We add all the numbers together, and all the variables

7x-140=0

We move all terms containing x to the left, all other terms to the right

7x=140

x=140/7

x=20

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