11x+11X(x+1)+11(x+2)=360

Solution for 11x+11X(x+1)+11(x+2)=360 equation:

11x+11x(x+1)+11(x+2)=360

We move all terms to the left:

11x+11x(x+1)+11(x+2)-(360)=0

We multiply parentheses

11x^2+11x+11x+11x+22-360=0

We add all the numbers together, and all the variables

11x^2+33x-338=0

a = 11; b = 33; c = -338;
Δ = b2-4ac
Δ = 332-4·11·(-338)
Δ = 15961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{15961}}{2*11}=\frac{-33-\sqrt{15961}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{15961}}{2*11}=\frac{-33+\sqrt{15961}}{22}
$