11x+11x=-12(6-5x)+10(3-4x)

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Solution for 11x+11x=-12(6-5x)+10(3-4x) equation: 



11x+11x=-12(6-5x)+10(3-4x)

We move all terms to the left:

11x+11x-(-12(6-5x)+10(3-4x))=0

We add all the numbers together, and all the variables

11x+11x-(-12(-5x+6)+10(-4x+3))=0

We add all the numbers together, and all the variables

22x-(-12(-5x+6)+10(-4x+3))=0



We calculate terms in parentheses: -(-12(-5x+6)+10(-4x+3)), so:

-12(-5x+6)+10(-4x+3)

We multiply parentheses

60x-40x-72+30

We add all the numbers together, and all the variables

20x-42

Back to the equation:

-(20x-42)



We get rid of parentheses

22x-20x+42=0

We add all the numbers together, and all the variables

2x+42=0

We move all terms containing x to the left, all other terms to the right

2x=-42

x=-42/2

x=-21

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