11x+20+3x=8(4x-2)

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Solution for 11x+20+3x=8(4x-2) equation: 



11x+20+3x=8(4x-2)

We move all terms to the left:

11x+20+3x-(8(4x-2))=0

We add all the numbers together, and all the variables

14x-(8(4x-2))+20=0



We calculate terms in parentheses: -(8(4x-2)), so:

8(4x-2)

We multiply parentheses

32x-16

Back to the equation:

-(32x-16)



We get rid of parentheses

14x-32x+16+20=0

We add all the numbers together, and all the variables

-18x+36=0

We move all terms containing x to the left, all other terms to the right

-18x=-36

x=-36/-18

x=+2

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