11x+20+3x=8(4x-2)

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Solution for 11x+20+3x=8(4x-2) equation:



11x+20+3x=8(4x-2)
We move all terms to the left:
11x+20+3x-(8(4x-2))=0
We add all the numbers together, and all the variables
14x-(8(4x-2))+20=0
We calculate terms in parentheses: -(8(4x-2)), so:
8(4x-2)
We multiply parentheses
32x-16
Back to the equation:
-(32x-16)
We get rid of parentheses
14x-32x+16+20=0
We add all the numbers together, and all the variables
-18x+36=0
We move all terms containing x to the left, all other terms to the right
-18x=-36
x=-36/-18
x=+2

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