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11x+3-4x=5(x+3)
We move all terms to the left:
11x+3-4x-(5(x+3))=0
We add all the numbers together, and all the variables
7x-(5(x+3))+3=0
We calculate terms in parentheses: -(5(x+3)), so:We get rid of parentheses
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
7x-5x-15+3=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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