11x+3=4x2

Solution for 11x+3=4x2 equation:

11x+3=4x^2

We move all terms to the left:

11x+3-(4x^2)=0

determiningTheFunctionDomain
-4x^2+11x+3=0

a = -4; b = 11; c = +3;
Δ = b2-4ac
Δ = 112-4·(-4)·3
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-13}{2*-4}=\frac{-24}{-8}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+13}{2*-4}=\frac{2}{-8}
=-1/4
$