11x+40-(7x+4)=2(x-6)

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Solution for 11x+40-(7x+4)=2(x-6) equation: 



11x+40-(7x+4)=2(x-6)

We move all terms to the left:

11x+40-(7x+4)-(2(x-6))=0

We get rid of parentheses

11x-7x-(2(x-6))-4+40=0



We calculate terms in parentheses: -(2(x-6)), so:

2(x-6)

We multiply parentheses

2x-12

Back to the equation:

-(2x-12)



We add all the numbers together, and all the variables

4x-(2x-12)+36=0

We get rid of parentheses

4x-2x+12+36=0

We add all the numbers together, and all the variables

2x+48=0

We move all terms containing x to the left, all other terms to the right

2x=-48

x=-48/2

x=-24

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