11x+7+4(3x-10)=13(2x-5)-1

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Solution for 11x+7+4(3x-10)=13(2x-5)-1 equation: 



11x+7+4(3x-10)=13(2x-5)-1

We move all terms to the left:

11x+7+4(3x-10)-(13(2x-5)-1)=0

We multiply parentheses

11x+12x-(13(2x-5)-1)-40+7=0



We calculate terms in parentheses: -(13(2x-5)-1), so:

13(2x-5)-1

We multiply parentheses

26x-65-1

We add all the numbers together, and all the variables

26x-66

Back to the equation:

-(26x-66)



We add all the numbers together, and all the variables

23x-(26x-66)-33=0

We get rid of parentheses

23x-26x+66-33=0

We add all the numbers together, and all the variables

-3x+33=0

We move all terms containing x to the left, all other terms to the right

-3x=-33

x=-33/-3

x=+11

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