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11x-(x-15)=2x-(3+x)=-4
We move all terms to the left:
11x-(x-15)-(2x-(3+x))=0
We add all the numbers together, and all the variables
11x-(x-15)-(2x-(x+3))=0
We get rid of parentheses
11x-x-(2x-(x+3))+15=0
We calculate terms in parentheses: -(2x-(x+3)), so:We add all the numbers together, and all the variables
2x-(x+3)
We get rid of parentheses
2x-x-3
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
10x-(x-3)+15=0
We get rid of parentheses
10x-x+3+15=0
We add all the numbers together, and all the variables
9x+18=0
We move all terms containing x to the left, all other terms to the right
9x=-18
x=-18/9
x=-2
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