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11x-(x-5)=2x-(8+x)
We move all terms to the left:
11x-(x-5)-(2x-(8+x))=0
We add all the numbers together, and all the variables
11x-(x-5)-(2x-(x+8))=0
We get rid of parentheses
11x-x-(2x-(x+8))+5=0
We calculate terms in parentheses: -(2x-(x+8)), so:We add all the numbers together, and all the variables
2x-(x+8)
We get rid of parentheses
2x-x-8
We add all the numbers together, and all the variables
x-8
Back to the equation:
-(x-8)
10x-(x-8)+5=0
We get rid of parentheses
10x-x+8+5=0
We add all the numbers together, and all the variables
9x+13=0
We move all terms containing x to the left, all other terms to the right
9x=-13
x=-13/9
x=-1+4/9
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