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11x-(x-6)=2x-(2+x)
We move all terms to the left:
11x-(x-6)-(2x-(2+x))=0
We add all the numbers together, and all the variables
11x-(x-6)-(2x-(x+2))=0
We get rid of parentheses
11x-x-(2x-(x+2))+6=0
We calculate terms in parentheses: -(2x-(x+2)), so:We add all the numbers together, and all the variables
2x-(x+2)
We get rid of parentheses
2x-x-2
We add all the numbers together, and all the variables
x-2
Back to the equation:
-(x-2)
10x-(x-2)+6=0
We get rid of parentheses
10x-x+2+6=0
We add all the numbers together, and all the variables
9x+8=0
We move all terms containing x to the left, all other terms to the right
9x=-8
x=-8/9
x=-8/9
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