11x-2+x-6=4(x+3)+8(x+12)

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Solution for 11x-2+x-6=4(x+3)+8(x+12) equation: 



11x-2+x-6=4(x+3)+8(x+12)

We move all terms to the left:

11x-2+x-6-(4(x+3)+8(x+12))=0

We add all the numbers together, and all the variables

12x-(4(x+3)+8(x+12))-8=0



We calculate terms in parentheses: -(4(x+3)+8(x+12)), so:

4(x+3)+8(x+12)

We multiply parentheses

4x+8x+12+96

We add all the numbers together, and all the variables

12x+108

Back to the equation:

-(12x+108)



We get rid of parentheses

12x-12x-108-8=0

We add all the numbers together, and all the variables

-116!=0

There is no solution for this equation

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