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11x/x+3=8x-9/x+3
We move all terms to the left:
11x/x+3-(8x-9/x+3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
11x/x-8x+9/x-3+3=0
We multiply all the terms by the denominator
11x-8x*x-3*x+3*x+9=0
We add all the numbers together, and all the variables
11x-8x*x+9=0
Wy multiply elements
-8x^2+11x+9=0
a = -8; b = 11; c = +9;
Δ = b2-4ac
Δ = 112-4·(-8)·9
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{409}}{2*-8}=\frac{-11-\sqrt{409}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{409}}{2*-8}=\frac{-11+\sqrt{409}}{-16} $
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