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11x^2+14x=2685
We move all terms to the left:
11x^2+14x-(2685)=0
a = 11; b = 14; c = -2685;
Δ = b2-4ac
Δ = 142-4·11·(-2685)
Δ = 118336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{118336}=344$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-344}{2*11}=\frac{-358}{22} =-16+3/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+344}{2*11}=\frac{330}{22} =15 $
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