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11x^2+67x+6=0
a = 11; b = 67; c = +6;
Δ = b2-4ac
Δ = 672-4·11·6
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-65}{2*11}=\frac{-132}{22} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+65}{2*11}=\frac{-2}{22} =-1/11 $
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