11x2+7=18x

Solution for 11x2+7=18x equation:

11x^2+7=18x

We move all terms to the left:

11x^2+7-(18x)=0

a = 11; b = -18; c = +7;
Δ = b2-4ac
Δ = -182-4·11·7
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-4}{2*11}=\frac{14}{22}
=7/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+4}{2*11}=\frac{22}{22}
=1
$