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11x^2+7x-6.5=0
a = 11; b = 7; c = -6.5;
Δ = b2-4ac
Δ = 72-4·11·(-6.5)
Δ = 335
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{335}}{2*11}=\frac{-7-\sqrt{335}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{335}}{2*11}=\frac{-7+\sqrt{335}}{22} $
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