11x2+x2=(4x+8)(3x-3)

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Solution for 11x2+x2=(4x+8)(3x-3) equation: 



11x^2+x2=(4x+8)(3x-3)

We move all terms to the left:

11x^2+x2-((4x+8)(3x-3))=0

We add all the numbers together, and all the variables

12x^2-((4x+8)(3x-3))=0

We multiply parentheses ..

12x^2-((+12x^2-12x+24x-24))=0



We calculate terms in parentheses: -((+12x^2-12x+24x-24)), so:

(+12x^2-12x+24x-24)

We get rid of parentheses

12x^2-12x+24x-24

We add all the numbers together, and all the variables

12x^2+12x-24

Back to the equation:

-(12x^2+12x-24)



We get rid of parentheses

12x^2-12x^2-12x+24=0

We add all the numbers together, and all the variables

-12x+24=0

We move all terms containing x to the left, all other terms to the right

-12x=-24

x=-24/-12

x=+2

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